6(x-5)+4x=(4x+2)-3x+1

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Solution for 6(x-5)+4x=(4x+2)-3x+1 equation: 



6(x-5)+4x=(4x+2)-3x+1

We move all terms to the left:

6(x-5)+4x-((4x+2)-3x+1)=0

We add all the numbers together, and all the variables

4x+6(x-5)-((4x+2)-3x+1)=0

We multiply parentheses

4x+6x-((4x+2)-3x+1)-30=0



We calculate terms in parentheses: -((4x+2)-3x+1), so:

(4x+2)-3x+1

We add all the numbers together, and all the variables

-3x+(4x+2)+1

We get rid of parentheses

-3x+4x+2+1

We add all the numbers together, and all the variables

x+3

Back to the equation:

-(x+3)



We add all the numbers together, and all the variables

10x-(x+3)-30=0

We get rid of parentheses

10x-x-3-30=0

We add all the numbers together, and all the variables

9x-33=0

We move all terms containing x to the left, all other terms to the right

9x=33

x=33/9

x=3+2/3

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