6(x-5)-3(x-2)=12x+18

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Solution for 6(x-5)-3(x-2)=12x+18 equation: 



6(x-5)-3(x-2)=12x+18

We move all terms to the left:

6(x-5)-3(x-2)-(12x+18)=0

We multiply parentheses

6x-3x-(12x+18)-30+6=0

We get rid of parentheses

6x-3x-12x-18-30+6=0

We add all the numbers together, and all the variables

-9x-42=0

We move all terms containing x to the left, all other terms to the right

-9x=42

x=42/-9

x=-4+2/3

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