6(x-5)=2(10+2x)

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Solution for 6(x-5)=2(10+2x) equation: 



6(x-5)=2(10+2x)

We move all terms to the left:

6(x-5)-(2(10+2x))=0

We add all the numbers together, and all the variables

6(x-5)-(2(2x+10))=0

We multiply parentheses

6x-(2(2x+10))-30=0



We calculate terms in parentheses: -(2(2x+10)), so:

2(2x+10)

We multiply parentheses

4x+20

Back to the equation:

-(4x+20)



We get rid of parentheses

6x-4x-20-30=0

We add all the numbers together, and all the variables

2x-50=0

We move all terms containing x to the left, all other terms to the right

2x=50

x=50/2

x=25

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