6(x-5)=2(10+3x)+10

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Solution for 6(x-5)=2(10+3x)+10 equation: 



6(x-5)=2(10+3x)+10

We move all terms to the left:

6(x-5)-(2(10+3x)+10)=0

We add all the numbers together, and all the variables

6(x-5)-(2(3x+10)+10)=0

We multiply parentheses

6x-(2(3x+10)+10)-30=0



We calculate terms in parentheses: -(2(3x+10)+10), so:

2(3x+10)+10

We multiply parentheses

6x+20+10

We add all the numbers together, and all the variables

6x+30

Back to the equation:

-(6x+30)



We get rid of parentheses

6x-6x-30-30=0

We add all the numbers together, and all the variables

-60!=0

There is no solution for this equation

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