6(x-5)=2(4x+1)

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Solution for 6(x-5)=2(4x+1) equation: 



6(x-5)=2(4x+1)

We move all terms to the left:

6(x-5)-(2(4x+1))=0

We multiply parentheses

6x-(2(4x+1))-30=0



We calculate terms in parentheses: -(2(4x+1)), so:

2(4x+1)

We multiply parentheses

8x+2

Back to the equation:

-(8x+2)



We get rid of parentheses

6x-8x-2-30=0

We add all the numbers together, and all the variables

-2x-32=0

We move all terms containing x to the left, all other terms to the right

-2x=32

x=32/-2

x=-16

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