6(x-5)=4(x+3)+18

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Solution for 6(x-5)=4(x+3)+18 equation: 



6(x-5)=4(x+3)+18

We move all terms to the left:

6(x-5)-(4(x+3)+18)=0

We multiply parentheses

6x-(4(x+3)+18)-30=0



We calculate terms in parentheses: -(4(x+3)+18), so:

4(x+3)+18

We multiply parentheses

4x+12+18

We add all the numbers together, and all the variables

4x+30

Back to the equation:

-(4x+30)



We get rid of parentheses

6x-4x-30-30=0

We add all the numbers together, and all the variables

2x-60=0

We move all terms containing x to the left, all other terms to the right

2x=60

x=60/2

x=30

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