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6(x-5)=4x-(3-x)
We move all terms to the left:
6(x-5)-(4x-(3-x))=0
We add all the numbers together, and all the variables
6(x-5)-(4x-(-1x+3))=0
We multiply parentheses
6x-(4x-(-1x+3))-30=0
We calculate terms in parentheses: -(4x-(-1x+3)), so:We get rid of parentheses
4x-(-1x+3)
We get rid of parentheses
4x+1x-3
We add all the numbers together, and all the variables
5x-3
Back to the equation:
-(5x-3)
6x-5x+3-30=0
We add all the numbers together, and all the variables
x-27=0
We move all terms containing x to the left, all other terms to the right
x=27
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