6(x-5)=9(x-27)

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Solution for 6(x-5)=9(x-27) equation: 



6(x-5)=9(x-27)

We move all terms to the left:

6(x-5)-(9(x-27))=0

We multiply parentheses

6x-(9(x-27))-30=0



We calculate terms in parentheses: -(9(x-27)), so:

9(x-27)

We multiply parentheses

9x-243

Back to the equation:

-(9x-243)



We get rid of parentheses

6x-9x+243-30=0

We add all the numbers together, and all the variables

-3x+213=0

We move all terms containing x to the left, all other terms to the right

-3x=-213

x=-213/-3

x=+71

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