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6(x-6)+46=2(3x+5)
We move all terms to the left:
6(x-6)+46-(2(3x+5))=0
We multiply parentheses
6x-(2(3x+5))-36+46=0
We calculate terms in parentheses: -(2(3x+5)), so:We add all the numbers together, and all the variables
2(3x+5)
We multiply parentheses
6x+10
Back to the equation:
-(6x+10)
6x-(6x+10)+10=0
We get rid of parentheses
6x-6x-10+10=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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