6(x-7)+2(x-3)=16

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Solution for 6(x-7)+2(x-3)=16 equation: 



6(x-7)+2(x-3)=16

We move all terms to the left:

6(x-7)+2(x-3)-(16)=0

We multiply parentheses

6x+2x-42-6-16=0

We add all the numbers together, and all the variables

8x-64=0

We move all terms containing x to the left, all other terms to the right

8x=64

x=64/8

x=8

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