6(x-7)+20=4(x-5)

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Solution for 6(x-7)+20=4(x-5) equation: 



6(x-7)+20=4(x-5)

We move all terms to the left:

6(x-7)+20-(4(x-5))=0

We multiply parentheses

6x-(4(x-5))-42+20=0



We calculate terms in parentheses: -(4(x-5)), so:

4(x-5)

We multiply parentheses

4x-20

Back to the equation:

-(4x-20)



We add all the numbers together, and all the variables

6x-(4x-20)-22=0

We get rid of parentheses

6x-4x+20-22=0

We add all the numbers together, and all the variables

2x-2=0

We move all terms containing x to the left, all other terms to the right

2x=2

x=2/2

x=1

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