6(x-8)+20=4(x-6)

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Solution for 6(x-8)+20=4(x-6) equation: 



6(x-8)+20=4(x-6)

We move all terms to the left:

6(x-8)+20-(4(x-6))=0

We multiply parentheses

6x-(4(x-6))-48+20=0



We calculate terms in parentheses: -(4(x-6)), so:

4(x-6)

We multiply parentheses

4x-24

Back to the equation:

-(4x-24)



We add all the numbers together, and all the variables

6x-(4x-24)-28=0

We get rid of parentheses

6x-4x+24-28=0

We add all the numbers together, and all the variables

2x-4=0

We move all terms containing x to the left, all other terms to the right

2x=4

x=4/2

x=2

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