6(x/4+2)-8=4x+20

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Solution for 6(x/4+2)-8=4x+20 equation: 



6(x/4+2)-8=4x+20

We move all terms to the left:

6(x/4+2)-8-(4x+20)=0

We multiply parentheses

6x-(4x+20)+12-8=0

We get rid of parentheses

6x-4x-20+12-8=0

We add all the numbers together, and all the variables

2x-16=0

We move all terms containing x to the left, all other terms to the right

2x=16

x=16/2

x=8

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