6(x=2)+2x-4=8(x-2)+8

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Solution for 6(x=2)+2x-4=8(x-2)+8 equation: 



6(x=2)+2x-4=8(x-2)+8

We move all terms to the left:

6(x-(2)+2x-4)=0

We add all the numbers together, and all the variables

6(3x-6)=0

We multiply parentheses

18x-36=0

We move all terms containing x to the left, all other terms to the right

18x=36

x=36/18

x=2

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