6(y+1)+2(y-5)=1

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Solution for 6(y+1)+2(y-5)=1 equation: 



6(y+1)+2(y-5)=1

We move all terms to the left:

6(y+1)+2(y-5)-(1)=0

We multiply parentheses

6y+2y+6-10-1=0

We add all the numbers together, and all the variables

8y-5=0

We move all terms containing y to the left, all other terms to the right

8y=5

y=5/8

y=5/8

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