6(y+1)+8y=2(y-3)

Solution for 6(y+1)+8y=2(y-3) equation:

Simplifying
6(y + 1) + 8y = 2(y + -3)

Reorder the terms:
6(1 + y) + 8y = 2(y + -3)
(1 * 6 + y * 6) + 8y = 2(y + -3)
(6 + 6y) + 8y = 2(y + -3)

Combine like terms: 6y + 8y = 14y
6 + 14y = 2(y + -3)

Reorder the terms:
6 + 14y = 2(-3 + y)
6 + 14y = (-3 * 2 + y * 2)
6 + 14y = (-6 + 2y)

Solving
6 + 14y = -6 + 2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2y' to each side of the equation.
6 + 14y + -2y = -6 + 2y + -2y

Combine like terms: 14y + -2y = 12y
6 + 12y = -6 + 2y + -2y

Combine like terms: 2y + -2y = 0
6 + 12y = -6 + 0
6 + 12y = -6

Add '-6' to each side of the equation.
6 + -6 + 12y = -6 + -6

Combine like terms: 6 + -6 = 0
0 + 12y = -6 + -6
12y = -6 + -6

Combine like terms: -6 + -6 = -12
12y = -12

Divide each side by '12'.
y = -1

Simplifying
y = -1