6(y+1)-10=4(y-1)+2y

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Solution for 6(y+1)-10=4(y-1)+2y equation:


Simplifying
6(y + 1) + -10 = 4(y + -1) + 2y

Reorder the terms:
6(1 + y) + -10 = 4(y + -1) + 2y
(1 * 6 + y * 6) + -10 = 4(y + -1) + 2y
(6 + 6y) + -10 = 4(y + -1) + 2y

Reorder the terms:
6 + -10 + 6y = 4(y + -1) + 2y

Combine like terms: 6 + -10 = -4
-4 + 6y = 4(y + -1) + 2y

Reorder the terms:
-4 + 6y = 4(-1 + y) + 2y
-4 + 6y = (-1 * 4 + y * 4) + 2y
-4 + 6y = (-4 + 4y) + 2y

Combine like terms: 4y + 2y = 6y
-4 + 6y = -4 + 6y

Add '4' to each side of the equation.
-4 + 4 + 6y = -4 + 4 + 6y

Combine like terms: -4 + 4 = 0
0 + 6y = -4 + 4 + 6y
6y = -4 + 4 + 6y

Combine like terms: -4 + 4 = 0
6y = 0 + 6y
6y = 6y

Add '-6y' to each side of the equation.
6y + -6y = 6y + -6y

Combine like terms: 6y + -6y = 0
0 = 6y + -6y

Combine like terms: 6y + -6y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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