6(y+1)-10=4(y-1)+4y

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Solution for 6(y+1)-10=4(y-1)+4y equation: 



6(y+1)-10=4(y-1)+4y

We move all terms to the left:

6(y+1)-10-(4(y-1)+4y)=0

We multiply parentheses

6y-(4(y-1)+4y)+6-10=0



We calculate terms in parentheses: -(4(y-1)+4y), so:

4(y-1)+4y

We add all the numbers together, and all the variables

4y+4(y-1)

We multiply parentheses

4y+4y-4

We add all the numbers together, and all the variables

8y-4

Back to the equation:

-(8y-4)



We add all the numbers together, and all the variables

6y-(8y-4)-4=0

We get rid of parentheses

6y-8y+4-4=0

We add all the numbers together, and all the variables

-2y=0

y=0/-2

y=0

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