6(y+1)=2(1-3y)-8

Solution for 6(y+1)=2(1-3y)-8 equation:

6(y+1)=2(1-3y)-8

We move all terms to the left:

6(y+1)-(2(1-3y)-8)=0

We add all the numbers together, and all the variables

6(y+1)-(2(-3y+1)-8)=0

We multiply parentheses

6y-(2(-3y+1)-8)+6=0


We calculate terms in parentheses: -(2(-3y+1)-8), so:

2(-3y+1)-8

We multiply parentheses

-6y+2-8

We add all the numbers together, and all the variables

-6y-6

Back to the equation:

-(-6y-6)


We get rid of parentheses

6y+6y+6+6=0

We add all the numbers together, and all the variables

12y+12=0

We move all terms containing y to the left, all other terms to the right

12y=-12

y=-12/12

y=-1