6(y+1)=2(3y+3)

Solution for 6(y+1)=2(3y+3) equation:

Simplifying
6(y + 1) = 2(3y + 3)

Reorder the terms:
6(1 + y) = 2(3y + 3)
(1 * 6 + y * 6) = 2(3y + 3)
(6 + 6y) = 2(3y + 3)

Reorder the terms:
6 + 6y = 2(3 + 3y)
6 + 6y = (3 * 2 + 3y * 2)
6 + 6y = (6 + 6y)

Add '-6' to each side of the equation.
6 + -6 + 6y = 6 + -6 + 6y

Combine like terms: 6 + -6 = 0
0 + 6y = 6 + -6 + 6y
6y = 6 + -6 + 6y

Combine like terms: 6 + -6 = 0
6y = 0 + 6y
6y = 6y

Add '-6y' to each side of the equation.
6y + -6y = 6y + -6y

Combine like terms: 6y + -6y = 0
0 = 6y + -6y

Combine like terms: 6y + -6y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.