6(y+1)=32

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Solution for 6(y+1)=32 equation: 



6(y+1)=32

We move all terms to the left:

6(y+1)-(32)=0

We multiply parentheses

6y+6-32=0

We add all the numbers together, and all the variables

6y-26=0

We move all terms containing y to the left, all other terms to the right

6y=26

y=26/6

y=4+1/3

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