6(y+1)=3y+3

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Solution for 6(y+1)=3y+3 equation:



6(y+1)=3y+3
We move all terms to the left:
6(y+1)-(3y+3)=0
We multiply parentheses
6y-(3y+3)+6=0
We get rid of parentheses
6y-3y-3+6=0
We add all the numbers together, and all the variables
3y+3=0
We move all terms containing y to the left, all other terms to the right
3y=-3
y=-3/3
y=-1

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