6(y+1)=3y+3

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Solution for 6(y+1)=3y+3 equation: 



6(y+1)=3y+3

We move all terms to the left:

6(y+1)-(3y+3)=0

We multiply parentheses

6y-(3y+3)+6=0

We get rid of parentheses

6y-3y-3+6=0

We add all the numbers together, and all the variables

3y+3=0

We move all terms containing y to the left, all other terms to the right

3y=-3

y=-3/3

y=-1

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