6(y+1)=48/7

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Solution for 6(y+1)=48/7 equation:



6(y+1)=48/7
We move all terms to the left:
6(y+1)-(48/7)=0
We add all the numbers together, and all the variables
6(y+1)-(+48/7)=0
We multiply parentheses
6y+6-(+48/7)=0
We get rid of parentheses
6y+6-48/7=0
We multiply all the terms by the denominator
6y*7-48+6*7=0
We add all the numbers together, and all the variables
6y*7-6=0
Wy multiply elements
42y-6=0
We move all terms containing y to the left, all other terms to the right
42y=6
y=6/42
y=1/7

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