6(y+10)+y=2(y+3)-8

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Solution for 6(y+10)+y=2(y+3)-8 equation: 



6(y+10)+y=2(y+3)-8

We move all terms to the left:

6(y+10)+y-(2(y+3)-8)=0

We add all the numbers together, and all the variables

y+6(y+10)-(2(y+3)-8)=0

We multiply parentheses

y+6y-(2(y+3)-8)+60=0



We calculate terms in parentheses: -(2(y+3)-8), so:

2(y+3)-8

We multiply parentheses

2y+6-8

We add all the numbers together, and all the variables

2y-2

Back to the equation:

-(2y-2)



We add all the numbers together, and all the variables

7y-(2y-2)+60=0

We get rid of parentheses

7y-2y+2+60=0

We add all the numbers together, and all the variables

5y+62=0

We move all terms containing y to the left, all other terms to the right

5y=-62

y=-62/5

y=-12+2/5

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