6(y+2)+y=4(y+2)-5

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Solution for 6(y+2)+y=4(y+2)-5 equation: 


Simplifying
6(y + 2) + y = 4(y + 2) + -5

Reorder the terms:
6(2 + y) + y = 4(y + 2) + -5
(2 * 6 + y * 6) + y = 4(y + 2) + -5
(12 + 6y) + y = 4(y + 2) + -5

Combine like terms: 6y + y = 7y
12 + 7y = 4(y + 2) + -5

Reorder the terms:
12 + 7y = 4(2 + y) + -5
12 + 7y = (2 * 4 + y * 4) + -5
12 + 7y = (8 + 4y) + -5

Reorder the terms:
12 + 7y = 8 + -5 + 4y

Combine like terms: 8 + -5 = 3
12 + 7y = 3 + 4y

Solving
12 + 7y = 3 + 4y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4y' to each side of the equation.
12 + 7y + -4y = 3 + 4y + -4y

Combine like terms: 7y + -4y = 3y
12 + 3y = 3 + 4y + -4y

Combine like terms: 4y + -4y = 0
12 + 3y = 3 + 0
12 + 3y = 3

Add '-12' to each side of the equation.
12 + -12 + 3y = 3 + -12

Combine like terms: 12 + -12 = 0
0 + 3y = 3 + -12
3y = 3 + -12

Combine like terms: 3 + -12 = -9
3y = -9

Divide each side by '3'.
y = -3

Simplifying
y = -3

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