6(y+2)-4(y+1)=12

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Solution for 6(y+2)-4(y+1)=12 equation: 


Simplifying
6(y + 2) + -4(y + 1) = 12

Reorder the terms:
6(2 + y) + -4(y + 1) = 12
(2 * 6 + y * 6) + -4(y + 1) = 12
(12 + 6y) + -4(y + 1) = 12

Reorder the terms:
12 + 6y + -4(1 + y) = 12
12 + 6y + (1 * -4 + y * -4) = 12
12 + 6y + (-4 + -4y) = 12

Reorder the terms:
12 + -4 + 6y + -4y = 12

Combine like terms: 12 + -4 = 8
8 + 6y + -4y = 12

Combine like terms: 6y + -4y = 2y
8 + 2y = 12

Solving
8 + 2y = 12

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + 2y = 12 + -8

Combine like terms: 8 + -8 = 0
0 + 2y = 12 + -8
2y = 12 + -8

Combine like terms: 12 + -8 = 4
2y = 4

Divide each side by '2'.
y = 2

Simplifying
y = 2

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