6(y+2)-y=-8

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Solution for 6(y+2)-y=-8 equation: 



6(y+2)-y=-8

We move all terms to the left:

6(y+2)-y-(-8)=0

We add all the numbers together, and all the variables

-1y+6(y+2)+8=0

We multiply parentheses

-1y+6y+12+8=0

We add all the numbers together, and all the variables

5y+20=0

We move all terms containing y to the left, all other terms to the right

5y=-20

y=-20/5

y=-4

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