6(y+2)=-2(6y-4)+4y

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Solution for 6(y+2)=-2(6y-4)+4y equation: 



6(y+2)=-2(6y-4)+4y

We move all terms to the left:

6(y+2)-(-2(6y-4)+4y)=0

We multiply parentheses

6y-(-2(6y-4)+4y)+12=0



We calculate terms in parentheses: -(-2(6y-4)+4y), so:

-2(6y-4)+4y

We add all the numbers together, and all the variables

4y-2(6y-4)

We multiply parentheses

4y-12y+8

We add all the numbers together, and all the variables

-8y+8

Back to the equation:

-(-8y+8)



We get rid of parentheses

6y+8y-8+12=0

We add all the numbers together, and all the variables

14y+4=0

We move all terms containing y to the left, all other terms to the right

14y=-4

y=-4/14

y=-2/7

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