6(y+2)=-4(4y-1)+8y

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Solution for 6(y+2)=-4(4y-1)+8y equation: 



6(y+2)=-4(4y-1)+8y

We move all terms to the left:

6(y+2)-(-4(4y-1)+8y)=0

We multiply parentheses

6y-(-4(4y-1)+8y)+12=0



We calculate terms in parentheses: -(-4(4y-1)+8y), so:

-4(4y-1)+8y

We add all the numbers together, and all the variables

8y-4(4y-1)

We multiply parentheses

8y-16y+4

We add all the numbers together, and all the variables

-8y+4

Back to the equation:

-(-8y+4)



We get rid of parentheses

6y+8y-4+12=0

We add all the numbers together, and all the variables

14y+8=0

We move all terms containing y to the left, all other terms to the right

14y=-8

y=-8/14

y=-4/7

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