6(y+2)=2(7y-5)+4y

Solution for 6(y+2)=2(7y-5)+4y equation:

6(y+2)=2(7y-5)+4y

We move all terms to the left:

6(y+2)-(2(7y-5)+4y)=0

We multiply parentheses

6y-(2(7y-5)+4y)+12=0


We calculate terms in parentheses: -(2(7y-5)+4y), so:

2(7y-5)+4y

We add all the numbers together, and all the variables

4y+2(7y-5)

We multiply parentheses

4y+14y-10

We add all the numbers together, and all the variables

18y-10

Back to the equation:

-(18y-10)


We get rid of parentheses

6y-18y+10+12=0

We add all the numbers together, and all the variables

-12y+22=0

We move all terms containing y to the left, all other terms to the right

-12y=-22

y=-22/-12

y=1+5/6