6(y+2)=8(y+1)

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Solution for 6(y+2)=8(y+1) equation: 



6(y+2)=8(y+1)

We move all terms to the left:

6(y+2)-(8(y+1))=0

We multiply parentheses

6y-(8(y+1))+12=0



We calculate terms in parentheses: -(8(y+1)), so:

8(y+1)

We multiply parentheses

8y+8

Back to the equation:

-(8y+8)



We get rid of parentheses

6y-8y-8+12=0

We add all the numbers together, and all the variables

-2y+4=0

We move all terms containing y to the left, all other terms to the right

-2y=-4

y=-4/-2

y=+2

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