6(y+2)=8y-4

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Solution for 6(y+2)=8y-4 equation: 



6(y+2)=8y-4

We move all terms to the left:

6(y+2)-(8y-4)=0

We multiply parentheses

6y-(8y-4)+12=0

We get rid of parentheses

6y-8y+4+12=0

We add all the numbers together, and all the variables

-2y+16=0

We move all terms containing y to the left, all other terms to the right

-2y=-16

y=-16/-2

y=+8

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