6(y+2)=9y-18

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Solution for 6(y+2)=9y-18 equation: 



6(y+2)=9y-18

We move all terms to the left:

6(y+2)-(9y-18)=0

We multiply parentheses

6y-(9y-18)+12=0

We get rid of parentheses

6y-9y+18+12=0

We add all the numbers together, and all the variables

-3y+30=0

We move all terms containing y to the left, all other terms to the right

-3y=-30

y=-30/-3

y=+10

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