6(y+3)-(y-2)=18

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Solution for 6(y+3)-(y-2)=18 equation: 



6(y+3)-(y-2)=18

We move all terms to the left:

6(y+3)-(y-2)-(18)=0

We multiply parentheses

6y-(y-2)+18-18=0

We get rid of parentheses

6y-y+2+18-18=0

We add all the numbers together, and all the variables

5y+2=0

We move all terms containing y to the left, all other terms to the right

5y=-2

y=-2/5

y=-2/5

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