6(y+3)-2(1-5y)=16y-7

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Solution for 6(y+3)-2(1-5y)=16y-7 equation: 


Simplifying
6(y + 3) + -2(1 + -5y) = 16y + -7

Reorder the terms:
6(3 + y) + -2(1 + -5y) = 16y + -7
(3 * 6 + y * 6) + -2(1 + -5y) = 16y + -7
(18 + 6y) + -2(1 + -5y) = 16y + -7
18 + 6y + (1 * -2 + -5y * -2) = 16y + -7
18 + 6y + (-2 + 10y) = 16y + -7

Reorder the terms:
18 + -2 + 6y + 10y = 16y + -7

Combine like terms: 18 + -2 = 16
16 + 6y + 10y = 16y + -7

Combine like terms: 6y + 10y = 16y
16 + 16y = 16y + -7

Reorder the terms:
16 + 16y = -7 + 16y

Add '-16y' to each side of the equation.
16 + 16y + -16y = -7 + 16y + -16y

Combine like terms: 16y + -16y = 0
16 + 0 = -7 + 16y + -16y
16 = -7 + 16y + -16y

Combine like terms: 16y + -16y = 0
16 = -7 + 0
16 = -7

Solving
16 = -7

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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