6(y+3)=-2(3y+9)

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Solution for 6(y+3)=-2(3y+9) equation: 



6(y+3)=-2(3y+9)

We move all terms to the left:

6(y+3)-(-2(3y+9))=0

We multiply parentheses

6y-(-2(3y+9))+18=0



We calculate terms in parentheses: -(-2(3y+9)), so:

-2(3y+9)

We multiply parentheses

-6y-18

Back to the equation:

-(-6y-18)



We get rid of parentheses

6y+6y+18+18=0

We add all the numbers together, and all the variables

12y+36=0

We move all terms containing y to the left, all other terms to the right

12y=-36

y=-36/12

y=-3

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