6(y+3)=-2(4y-4)+2y

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Solution for 6(y+3)=-2(4y-4)+2y equation: 



6(y+3)=-2(4y-4)+2y

We move all terms to the left:

6(y+3)-(-2(4y-4)+2y)=0

We multiply parentheses

6y-(-2(4y-4)+2y)+18=0



We calculate terms in parentheses: -(-2(4y-4)+2y), so:

-2(4y-4)+2y

We add all the numbers together, and all the variables

2y-2(4y-4)

We multiply parentheses

2y-8y+8

We add all the numbers together, and all the variables

-6y+8

Back to the equation:

-(-6y+8)



We get rid of parentheses

6y+6y-8+18=0

We add all the numbers together, and all the variables

12y+10=0

We move all terms containing y to the left, all other terms to the right

12y=-10

y=-10/12

y=-5/6

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