6(y+3)=-2y+10

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Solution for 6(y+3)=-2y+10 equation: 



6(y+3)=-2y+10

We move all terms to the left:

6(y+3)-(-2y+10)=0

We multiply parentheses

6y-(-2y+10)+18=0

We get rid of parentheses

6y+2y-10+18=0

We add all the numbers together, and all the variables

8y+8=0

We move all terms containing y to the left, all other terms to the right

8y=-8

y=-8/8

y=-1

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