6(y+3)=-3(4y-8)+3y

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Solution for 6(y+3)=-3(4y-8)+3y equation: 



6(y+3)=-3(4y-8)+3y

We move all terms to the left:

6(y+3)-(-3(4y-8)+3y)=0

We multiply parentheses

6y-(-3(4y-8)+3y)+18=0



We calculate terms in parentheses: -(-3(4y-8)+3y), so:

-3(4y-8)+3y

We add all the numbers together, and all the variables

3y-3(4y-8)

We multiply parentheses

3y-12y+24

We add all the numbers together, and all the variables

-9y+24

Back to the equation:

-(-9y+24)



We get rid of parentheses

6y+9y-24+18=0

We add all the numbers together, and all the variables

15y-6=0

We move all terms containing y to the left, all other terms to the right

15y=6

y=6/15

y=2/5

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