6(y+3)=-4(2y-3)+4y

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Solution for 6(y+3)=-4(2y-3)+4y equation: 



6(y+3)=-4(2y-3)+4y

We move all terms to the left:

6(y+3)-(-4(2y-3)+4y)=0

We multiply parentheses

6y-(-4(2y-3)+4y)+18=0



We calculate terms in parentheses: -(-4(2y-3)+4y), so:

-4(2y-3)+4y

We add all the numbers together, and all the variables

4y-4(2y-3)

We multiply parentheses

4y-8y+12

We add all the numbers together, and all the variables

-4y+12

Back to the equation:

-(-4y+12)



We get rid of parentheses

6y+4y-12+18=0

We add all the numbers together, and all the variables

10y+6=0

We move all terms containing y to the left, all other terms to the right

10y=-6

y=-6/10

y=-3/5

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