6(y+3)=3y+18

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Solution for 6(y+3)=3y+18 equation: 



6(y+3)=3y+18

We move all terms to the left:

6(y+3)-(3y+18)=0

We multiply parentheses

6y-(3y+18)+18=0

We get rid of parentheses

6y-3y-18+18=0

We add all the numbers together, and all the variables

3y=0

y=0/3

y=0

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