6(y+3)=4y+1

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Solution for 6(y+3)=4y+1 equation: 



6(y+3)=4y+1

We move all terms to the left:

6(y+3)-(4y+1)=0

We multiply parentheses

6y-(4y+1)+18=0

We get rid of parentheses

6y-4y-1+18=0

We add all the numbers together, and all the variables

2y+17=0

We move all terms containing y to the left, all other terms to the right

2y=-17

y=-17/2

y=-8+1/2

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