6(y+4)+3=57

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Solution for 6(y+4)+3=57 equation: 



6(y+4)+3=57

We move all terms to the left:

6(y+4)+3-(57)=0

We add all the numbers together, and all the variables

6(y+4)-54=0

We multiply parentheses

6y+24-54=0

We add all the numbers together, and all the variables

6y-30=0

We move all terms containing y to the left, all other terms to the right

6y=30

y=30/6

y=5

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