6(y+4)-3=3(2y+7)

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Solution for 6(y+4)-3=3(2y+7) equation: 



6(y+4)-3=3(2y+7)

We move all terms to the left:

6(y+4)-3-(3(2y+7))=0

We multiply parentheses

6y-(3(2y+7))+24-3=0



We calculate terms in parentheses: -(3(2y+7)), so:

3(2y+7)

We multiply parentheses

6y+21

Back to the equation:

-(6y+21)



We add all the numbers together, and all the variables

6y-(6y+21)+21=0

We get rid of parentheses

6y-6y-21+21=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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