6(y+4)=3y-(2y-4)

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Solution for 6(y+4)=3y-(2y-4) equation: 



6(y+4)=3y-(2y-4)

We move all terms to the left:

6(y+4)-(3y-(2y-4))=0

We multiply parentheses

6y-(3y-(2y-4))+24=0



We calculate terms in parentheses: -(3y-(2y-4)), so:

3y-(2y-4)

We get rid of parentheses

3y-2y+4

We add all the numbers together, and all the variables

y+4

Back to the equation:

-(y+4)



We get rid of parentheses

6y-y-4+24=0

We add all the numbers together, and all the variables

5y+20=0

We move all terms containing y to the left, all other terms to the right

5y=-20

y=-20/5

y=-4

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