6(y+5)=-4(3y-7)+2y

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Solution for 6(y+5)=-4(3y-7)+2y equation: 



6(y+5)=-4(3y-7)+2y

We move all terms to the left:

6(y+5)-(-4(3y-7)+2y)=0

We multiply parentheses

6y-(-4(3y-7)+2y)+30=0



We calculate terms in parentheses: -(-4(3y-7)+2y), so:

-4(3y-7)+2y

We add all the numbers together, and all the variables

2y-4(3y-7)

We multiply parentheses

2y-12y+28

We add all the numbers together, and all the variables

-10y+28

Back to the equation:

-(-10y+28)



We get rid of parentheses

6y+10y-28+30=0

We add all the numbers together, and all the variables

16y+2=0

We move all terms containing y to the left, all other terms to the right

16y=-2

y=-2/16

y=-1/8

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