6(y-1)-2=-4(-6y+3)-8y

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Solution for 6(y-1)-2=-4(-6y+3)-8y equation:



6(y-1)-2=-4(-6y+3)-8y
We move all terms to the left:
6(y-1)-2-(-4(-6y+3)-8y)=0
We multiply parentheses
6y-(-4(-6y+3)-8y)-6-2=0
We calculate terms in parentheses: -(-4(-6y+3)-8y), so:
-4(-6y+3)-8y
We add all the numbers together, and all the variables
-8y-4(-6y+3)
We multiply parentheses
-8y+24y-12
We add all the numbers together, and all the variables
16y-12
Back to the equation:
-(16y-12)
We add all the numbers together, and all the variables
6y-(16y-12)-8=0
We get rid of parentheses
6y-16y+12-8=0
We add all the numbers together, and all the variables
-10y+4=0
We move all terms containing y to the left, all other terms to the right
-10y=-4
y=-4/-10
y=2/5

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