6(y-1)-2=-4(-6y+3)-8y

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Solution for 6(y-1)-2=-4(-6y+3)-8y equation: 



6(y-1)-2=-4(-6y+3)-8y

We move all terms to the left:

6(y-1)-2-(-4(-6y+3)-8y)=0

We multiply parentheses

6y-(-4(-6y+3)-8y)-6-2=0



We calculate terms in parentheses: -(-4(-6y+3)-8y), so:

-4(-6y+3)-8y

We add all the numbers together, and all the variables

-8y-4(-6y+3)

We multiply parentheses

-8y+24y-12

We add all the numbers together, and all the variables

16y-12

Back to the equation:

-(16y-12)



We add all the numbers together, and all the variables

6y-(16y-12)-8=0

We get rid of parentheses

6y-16y+12-8=0

We add all the numbers together, and all the variables

-10y+4=0

We move all terms containing y to the left, all other terms to the right

-10y=-4

y=-4/-10

y=2/5

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