6(y-1)=4(y+2)

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Solution for 6(y-1)=4(y+2) equation: 



6(y-1)=4(y+2)

We move all terms to the left:

6(y-1)-(4(y+2))=0

We multiply parentheses

6y-(4(y+2))-6=0



We calculate terms in parentheses: -(4(y+2)), so:

4(y+2)

We multiply parentheses

4y+8

Back to the equation:

-(4y+8)



We get rid of parentheses

6y-4y-8-6=0

We add all the numbers together, and all the variables

2y-14=0

We move all terms containing y to the left, all other terms to the right

2y=14

y=14/2

y=7

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