6(y-1)=5y+2-2(-5y-2)

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Solution for 6(y-1)=5y+2-2(-5y-2) equation: 



6(y-1)=5y+2-2(-5y-2)

We move all terms to the left:

6(y-1)-(5y+2-2(-5y-2))=0

We multiply parentheses

6y-(5y+2-2(-5y-2))-6=0



We calculate terms in parentheses: -(5y+2-2(-5y-2)), so:

5y+2-2(-5y-2)

determiningTheFunctionDomain
5y-2(-5y-2)+2

We multiply parentheses

5y+10y+4+2

We add all the numbers together, and all the variables

15y+6

Back to the equation:

-(15y+6)



We get rid of parentheses

6y-15y-6-6=0

We add all the numbers together, and all the variables

-9y-12=0

We move all terms containing y to the left, all other terms to the right

-9y=12

y=12/-9

y=-1+1/3

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