6(y-2)+1=2(3y-5)

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Solution for 6(y-2)+1=2(3y-5) equation:


Simplifying
6(y + -2) + 1 = 2(3y + -5)

Reorder the terms:
6(-2 + y) + 1 = 2(3y + -5)
(-2 * 6 + y * 6) + 1 = 2(3y + -5)
(-12 + 6y) + 1 = 2(3y + -5)

Reorder the terms:
-12 + 1 + 6y = 2(3y + -5)

Combine like terms: -12 + 1 = -11
-11 + 6y = 2(3y + -5)

Reorder the terms:
-11 + 6y = 2(-5 + 3y)
-11 + 6y = (-5 * 2 + 3y * 2)
-11 + 6y = (-10 + 6y)

Add '-6y' to each side of the equation.
-11 + 6y + -6y = -10 + 6y + -6y

Combine like terms: 6y + -6y = 0
-11 + 0 = -10 + 6y + -6y
-11 = -10 + 6y + -6y

Combine like terms: 6y + -6y = 0
-11 = -10 + 0
-11 = -10

Solving
-11 = -10

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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